Finding a file from within PML

There is some functionality by using the file object and it's various methods, however it is quite limited

It only looks for the file in the directory provided and doesn't appear to search in sub-directories :

!v1 = object file('c:\temp\abc.txt')
!v2 = !v1.exists()

unlike below which would search all sub-directories and find all copies of files named as such : 

syscom 'start dir c:\temp.abc.txt /s' 

You can do something like this. 1000000 is picked to be larger than the possible count of all subdirs

!f = object file('c:\temp\NetGridAddinControl.cs')
if not !f.exists() then
    !dir = !f.directory()
    !subdirs = object array()
    !subdirs.appendarray(!dir.subdirs())
    
    do !i to 1000000
        if !i gt !subdirs.size() then
            $p not found
            break
        endif
        !dir = !subdirs[!i]
        !ff = object file(!dir.fullname() + '\' + !f.entry())
        if !ff.exists() then
            $p found:
            q var !ff.fullname()
            break
        endif
        !subdirs.appendarray(!dir.subdirs())
    enddo
endif

found:

<STRING> 'c:\temp\Samples\NetGridExample\NetGridAddinControl.cs'

Thanks for that.

I did something very similar, using the file object and methods like subdirs() and files() and managed to get my desired result.